For a differentiable function f : R R, suppose f'(x) = 3f(x) + , where R, f(0) = 1 and x - f(x) = 7. Then 9f(- e 3) is equal to .
Answer
61
Solution
f'(x) - 3f(x) = is a linear differential equation with I.F. = e-3x:
ddx (f e-3x ) = e-3x f e-3x = - 3e-3x + C
f(x) = Ce3x - 3
As x - , e3x 0, so - 3 = 7 = -21; and f(0) = 1 C + 7 = 1 C = -6
Thus f(x) = 7 - 6e3x, so f(- e 3) = 7 - 627 = 619
Hence 9f(- e 3) = 61
Answer: 61