Two slits in Young's experiment have widths in the ratio 1 : 25. The ratio of intensity at the maxima and minima in the interference pattern, I I is
- 49121
- 49
- 94
- 12149
Answer
(3) 94
Solution
Intensity width of the slit ⇒ I1I2 = 125
Amplitude I ⇒ a1a2 = 15
I I = (a1 + a2)2(a2 - a1)2 = (1 + 5)2(5 - 1)2
= 3616 = 94
Answer: (3)