Two radioactive substances A and B have decay constants 5 and respectively. At t = 0 they have the same number of nuclei. The ratio of number of nuclei of A to those of B will be ( 1e )2 after a time interval
- 4
- 2
- 12
- 14
Answer
(3) 12
Solution
By the law of radioactive decay, N = N0 e- t
⇒ NA = N0 e-5 t and NB = N0 e- t
⇒ NANB = e-4 t
Given NANB = ( 1e )2 = e-2
⇒ 4 t = 2
∴ t = 12
Answer: (3)