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Amines

JEE Main 2025 (Online) 23rd January Morning ShiftNumericalMedium📈 Topic in 18% papers+4
Ques. 1JEE Main 2025, 23 January (Morning Shift)

Consider the following sequence of reactions to produce major product (A) [figure] Molar mass of product (A) is g mol-1. (Given molar mass in g mol-1 of C : 12, H : 1, O : 16, Br : 80, N : 14, P : 31)

Answer

171

Solution

Concept: Br2/Fe brominates ring, Sn/HCl: -NO2 -NH2, NaNO2/HCl: diazonium, H3PO2: -N2+ -H.

[figure]

[figure]

∴ (A) = bromotoluene C7H7Br (the -NO2/-NH2 director is removed, so isomer does not matter).

Molar mass =84+7+80=171 g mol-1

Answer: 171

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Ques. 2JEE Main 2025, 23 January (Evening Shift)

Consider the following sequence of reactions. [figure] Total number of sp3 hybridised carbon atoms in the major product C formed is .

Ques. 3JEE Main 2025, 22 January (Morning Shift)

The products formed in the following reaction sequence are : [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 4JEE Main 2025, 22 January (Morning Shift)

Consider the following sequence of reactions : [figure] Molar mass of the product formed (A) is g mol-1.

Ques. 5JEE Main 2025, 22 January (Evening Shift)

Match the Compounds (List - I) with the appropriate Catalyst/ Reagents (List - II) for their reduction into corresponding amines. Choose the correct answer from the options given below :

  1. A-II, B-IV, C-III, D-I
  2. A-III, B-IV, C-II, D-I
  3. A-III, B-II, C-IV, D-I
  4. A-II, B-I, C-III, D-IV

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