If three moles of monoatomic gas ( = 53 ) is mixed with two moles of a diatomic gas ( = 75 ), the value of adiabatic exponent for the mixture is
- 1.35
- 1.52
- 1.40
- 1.75
Answer
(2) 1.52
Solution
CV: monoatomic 32R, diatomic 52R
CV,mix= 3 32R+2 52R3+2= 1910R
CP,mix=CV,mix+R= 2910R
mix= 2919 1.52
Answer: (2)