A cylindrical tube AB of length l, closed at both ends contains an ideal gas of 1 mol having molecular weight M. The tube is rotated in a horizontal plane with constant angular velocity about an axis perpendicular to AB and passing through the edge at end A, as shown in the figure. If PA and PB are the pressures at A and B respectively, then (Consider the temperature is same at all points in the tube) [figure]
- PB = PA e ( M 2 l23RT )
- PB = PA
- PB = PA e ( M 2 l22RT )
- PB = PA e ( M 2 l2RT )
Answer
(3) PB = PA e ( M 2 l22RT )
Solution
Take a thin layer of gas of thickness dr at distance r from the axis (cross-section a).
The net pressure force on it gives the centripetal force:
(P + dP)a - Pa = ( a dr) 2 r
dP = 2 r dr
For an ideal gas: = PMRT
dPP = M 2RTr dr
PAPB dPP = M 2RT 0l r dr
PBPA = M 2 l22RT
PB = PA e ( M 2 l22RT )
Answer: (3)