An elastic spring under tension of 3 N has a length a. Its length is b under tension 2 N. For its length (3a-2b), the value of tension will be N.
Answer
5
Solution
Hooke's law: T=k(L-L0), L0 = natural length
3=k(a-L0), 2=k(b-L0)
T=k(3a-2b-L0)
=3k(a-L0)-2k(b-L0)
=3 3-2 2=5 N
Answer: 5