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Electric Charges and Fields · Question 19

JEE Main 2025 (Online) 4th April Evening ShiftMCQMedium📈 Topic in 13% papers+4−1
1

A metallic ring is uniformly charged as shown in figure. AC and BD are two mutually perpendicular diameters. Electric field due to arc AB at 'O' is 'E' in magnitude. What would be the magnitude of electric field at 'O' due to arc ABC ? [figure]

  1. 2E
  2. Zero
  3. E/2
  4. 2E

Answer

(4) 2E

Solution

Field at the centre due to a uniformly charged arc (radius r, linear charge density ) subtending angle :

Earc= 2k r 2, directed along the bisector of the arc, away from it (positive charge)

Arc AB ( =90 ): E= 2k r 45 = 2k r, along the bisector of AB

Arc ABC = arc AB + arc BC; arc BC also gives a field of magnitude E, along its own bisector

The bisectors of AB and BC are 90 apart

EABC= E2+E2= 2E

(Check: semicircle, =180 : 2k r= 2 2k r= 2E)

Answer: (4)

JEE Main 2025 (Online) 4th April Evening Shift

Keep practising — Electric Charges and Fields

2

Consider two infinitely large plane parallel conducting plates as shown below. The plates are uniformly charged with a surface charge density + and -2 . The force experienced by a point charge +q placed at the mid point between two plates will be: [figure]

  1. 3 q4 0
  2. 3 q2 0
  3. q4 0
  4. q2 0
JEE Main 2025 (Online) 2nd April Morning Shift
3

A point charge +q is placed at the origin. A second point charge +9q is placed at (d, 0, 0) in Cartesian coordinate system. The point in between them where the electric field vanishes is:

  1. (3d/4, 0, 0)
  2. (d/4, 0, 0)
  3. (4d/3, 0, 0)
  4. (d/3, 0, 0)
JEE Main 2025 (Online) 2nd April Morning Shift
4

A small bob of mass 100 mg and charge +10 is connected to an insulating string of length 1 m. It is brought near to an infinitely long non-conducting sheet of charge density ' ' as shown in figure. If string subtends an angle of 45 with the sheet at equilibrium the charge density of sheet will be: (Given, 0 = 8.85 10-12 Fm and acceleration due to gravity, g = 10 ms2) [figure]

  1. 1.77 nC/m2
  2. 0.885 nC/m2
  3. 885 nC/m2
  4. 17.7 nC/m2
JEE Main 2025 (Online) 2nd April Morning Shift
5

Consider a circular loop that is uniformly charged and has a radius a 2. Find the position along the positive z-axis of the Cartesian coordinate system where the electric field is maximum if the ring was assumed to be placed in xy plane at the origin :

  1. a
  2. a/2
  3. 0
  4. a/ 2
JEE Main 2025 (Online) 2nd April Evening Shift
6

An electric dipole of mass m, charge q, and length l is placed in a uniform electric field E = E0 i. When the dipole is rotated slightly from its equilibrium position and released, the time period of its oscillations will be :

  1. 12 ml2qE0
  2. 2 ml2qE0
  3. 2 mlqE0
  4. 12 2mlqE0
JEE Main 2025 (Online) 29th January Morning Shift
7

Match List - I with List - II. Choose the correct answer from the options given below :

  1. (A)-(IV), (B)-(I), (C)-(III), (D)-(II)
  2. (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
  3. (A)-(III), (B)-(II), (C)-(IV), (D)-(I)
  4. (A)-(IV), (B)-(II), (C)-(III), (D)-(I)
JEE Main 2025 (Online) 29th January Morning Shift

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