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Electric Charges and Fields · Question 18

JEE Main 2025 (Online) 4th April Morning ShiftMCQMedium📈 Topic in 13% papers+4−1
1

Two small spherical balls of mass 10 g each with charges -2 and 2 , are attached to two ends of very light rigid rod of length 20 cm. The arrangement is now placed near an infinite non-conducting charge sheet with uniform charge density of 100 /m2 such that length of rod makes an angle of 30 with electric field generated by charge sheet. Net torque acting on the rod is: (Take 0 = 8.85 10-12 C2/Nm2)

  1. 1.12 Nm
  2. 2.24 Nm
  3. 11.2 Nm
  4. 112 Nm

Answer

(1) 1.12 Nm

Solution

The two balls form an electric dipole of moment p = q 2a = (2 10-6)(0.2) = 4 10-7 C m

Field of the infinite sheet (uniform): E = 2 0 = 100 10-62 8.85 10-12

E 5.65 106 N/C

Torque on a dipole in a uniform field: = pE

= 4 10-7 5.65 106 30

1.13 N m 1.12 N m

(The masses of the balls do not affect the torque.)

Answer: (1)

JEE Main 2025 (Online) 4th April Morning Shift

Keep practising — Electric Charges and Fields

2

A metallic ring is uniformly charged as shown in figure. AC and BD are two mutually perpendicular diameters. Electric field due to arc AB at 'O' is 'E' in magnitude. What would be the magnitude of electric field at 'O' due to arc ABC ? [figure]

  1. 2E
  2. Zero
  3. E/2
  4. 2E
JEE Main 2025 (Online) 4th April Evening Shift
3

Consider two infinitely large plane parallel conducting plates as shown below. The plates are uniformly charged with a surface charge density + and -2 . The force experienced by a point charge +q placed at the mid point between two plates will be: [figure]

  1. 3 q4 0
  2. 3 q2 0
  3. q4 0
  4. q2 0
JEE Main 2025 (Online) 2nd April Morning Shift
4

A point charge +q is placed at the origin. A second point charge +9q is placed at (d, 0, 0) in Cartesian coordinate system. The point in between them where the electric field vanishes is:

  1. (3d/4, 0, 0)
  2. (d/4, 0, 0)
  3. (4d/3, 0, 0)
  4. (d/3, 0, 0)
JEE Main 2025 (Online) 2nd April Morning Shift
5

A small bob of mass 100 mg and charge +10 is connected to an insulating string of length 1 m. It is brought near to an infinitely long non-conducting sheet of charge density ' ' as shown in figure. If string subtends an angle of 45 with the sheet at equilibrium the charge density of sheet will be: (Given, 0 = 8.85 10-12 Fm and acceleration due to gravity, g = 10 ms2) [figure]

  1. 1.77 nC/m2
  2. 0.885 nC/m2
  3. 885 nC/m2
  4. 17.7 nC/m2
JEE Main 2025 (Online) 2nd April Morning Shift
6

Consider a circular loop that is uniformly charged and has a radius a 2. Find the position along the positive z-axis of the Cartesian coordinate system where the electric field is maximum if the ring was assumed to be placed in xy plane at the origin :

  1. a
  2. a/2
  3. 0
  4. a/ 2
JEE Main 2025 (Online) 2nd April Evening Shift
7

An electric dipole of mass m, charge q, and length l is placed in a uniform electric field E = E0 i. When the dipole is rotated slightly from its equilibrium position and released, the time period of its oscillations will be :

  1. 12 ml2qE0
  2. 2 ml2qE0
  3. 2 mlqE0
  4. 12 2mlqE0
JEE Main 2025 (Online) 29th January Morning Shift
8

Match List - I with List - II. Choose the correct answer from the options given below :

  1. (A)-(IV), (B)-(I), (C)-(III), (D)-(II)
  2. (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
  3. (A)-(III), (B)-(II), (C)-(IV), (D)-(I)
  4. (A)-(IV), (B)-(II), (C)-(III), (D)-(I)
JEE Main 2025 (Online) 29th January Morning Shift

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