Which of the following arrangements do not give the correct picture of the trends indicated against them?
- F2 > Cl2 > Br2 > I2 : Bond dissociation energy
- F2 > Cl2 > Br2 > I2 : Electronegativity
- F2 > Cl2 > Br2 > I2 : Oxidizing power
- F2 > Cl2 > Br2 > I2 : Electron gain enthalpy
Answer
(1) F2 > Cl2 > Br2 > I2 : Bond dissociation energy, (4) F2 > Cl2 > Br2 > I2 : Electron gain enthalpy
Solution
(1) Bond dissociation enthalpy ( kJ mol-1): Cl2 (242.6) > Br2 (192.8) > F2 (158.8) > I2 (151.1).
∵ As per NCERT, the bond dissociation enthalpy of F2 is smaller than that of Cl2 due to large electron–electron repulsion among the lone pairs of the small F atoms.
⇒ The given order is incorrect.
(2) Electronegativity decreases down the group: F > Cl > Br > I ⇒ correct.
(3) Oxidising power: F2 > Cl2 > Br2 > I2 ⇒ correct.
(4) Negative electron gain enthalpy ( kJ mol-1): Cl (–349) > F (–333) > Br (–325) > I (–296).
∵ As per NCERT, F has a less negative electron gain enthalpy than Cl because of its small size (strong interelectronic repulsion in the compact 2p subshell).
⇒ The given order is incorrect.
∴ Arrangements (1) and (4) are incorrect.
Answer: (1), (4)