PYQSidePowered byPrepblink ExamsMy practice

Electrostatic Potential and Capacitance

JEE Main 2025 (Online) 24th January Evening ShiftMCQMedium📈 Topic in 16% papers+4−1
Ques. 1JEE Main 2025, 24 January (Evening Shift)

[figure] In the first configuration (1) as shown in the figure, four identical charges (q0) are kept at the corners A, B, C and D of square of side length 'a'. In the second configuration (2), the same charges are shifted to mid points G, E, H and F, of the square. If K= 14 0, the difference between the potential energies of configuration (2) and (1) is given by :

  1. Kq02a (4-2 2 )
  2. Kq02a (4 2-2 )
  3. Kq02a (3- 2 )
  4. Kq02a (3 2-2 )

Answer

(4) Kq02a (3 2-2 )

Solution

U= Kq02rij over the 6 pairs.

[figure]

(1): 4 sides a, 2 diagonals 2a: U1= Kq02a (4+ 2 )

(2): 4 sides a 2, 2 diagonals a: U2= Kq02a (4 2+2 )

U2-U1= Kq02a (3 2-2 )

Answer: (4)

Keep practising — Electrostatic Potential and Capacitance

Ques. 2JEE Main 2025, 23 January (Evening Shift)

Two point charges -4 and 4 , constituting an electric dipole, are placed at (-9,0,0) cm and (9,0,0) cm in a uniform electric field of strength 104 N C-1. The work done on the dipole in rotating it from the equilibrium through 180 is :

  1. 18.4 mJ
  2. 12.4 mJ
  3. 16.4 mJ
  4. 14.4 mJ
Ques. 3JEE Main 2025, 23 January (Evening Shift)

Two charges 7 and -4 are placed at (-7 cm,0,0) and (7 cm,0,0) respectively. Given, 0=8.85 10-12 C2 N-1 m-2, the electrostatic potential energy of the charge configuration is :

  1. -2.0 J
  2. -1.5 J
  3. -1.2 J
  4. -1.8 J
Ques. 4JEE Main 2025, 22 January (Morning Shift)

A parallel-plate capacitor of capacitance 40 is connected to a 100 V power supply. Now the intermediate space between the plates is filled with a dielectric material of dielectric constant K=2. Due to the introduction of dielectric material, the extra charge and the change in the electrostatic energy in the capacitor, respectively, are

  1. 8 mC and 2.0 J
  2. 4 mC and 0.2 J
  3. 2 mC and 0.2 J
  4. 2 mC and 0.4 J
Ques. 5JEE Main 2025, 22 January (Evening Shift)

For a short dipole placed at origin O , the dipole moment P is along x-axis, as shown in the figure. If the electric potential and electric field at A are V0 and E0, respectively, then the correct combination of the electric potential and electric field, respectively, at point B on the y-axis is given by [figure]

  1. V02 and E016
  2. zero and E08
  3. V0 and E04
  4. zero and E016

All Electrostatic Potential and Capacitance PYQs →

PDFDownload Electrostatic Potential and Capacitance PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Physics chapters