Number of and bonds present in ethylene molecule is respectively :
- 3 and 1
- 5 and 1
- 4 and 1
- 5 and 2
Answer
(2) 5 and 1
Solution
[figure]
Every single bond = 1 ; a double bond = 1 + 1
Four C–H bonds ⇒ 4
One C=C bond ⇒ 1 + 1
∴ = 4 + 1 = 5 and = 1
Answer: (2)