In single slit diffraction pattern, the wavelength of light used is 628 nm and slit width is 0.2 mm, the angular width of central maximum is 10-2 degrees. The value of is .
Answer
36
Solution
Angular width of central maximum: 2 = 2 a
= 2 628 10-90.2 10-3=6.28 10-3 rad
In degrees: 6.28 10-3 1803.14
=0.36 =36 10-2 degrees
=36
Answer: 36