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p-Block Elements (Group 15–18) · Question 15

JEE Main 2025 (Online) 2nd April Evening ShiftMCQEasy📈 Topic in 10% papers+4−1
1

The nature of oxide (TeO2) and hydride (TeH2) formed by Te, respectively are:

  1. Reducing and basic
  2. Reducing and acidic
  3. Oxidising and acidic
  4. Oxidising and basic

Answer

(3) Oxidising and acidic

Solution

Oxide: in group 16 the stability of the +6 state decreases and of the +4 state increases down the group (inert pair effect). As per NCERT, the reducing property of the dioxides decreases from SO2 to TeO2; SO2 is reducing while TeO2 is an oxidising agent.

Hydride: down the group the E–H bond enthalpy decreases, so H⁺ is released more easily and acidic character increases: H2O < H2S < H2Se < H2Te. H2Te (TeH2) is acidic.

Answer: (3)

JEE Main 2025 (Online) 2nd April Evening Shift

Keep practising — p-Block Elements (Group 15–18)

2

A group 15 element forms d - d bond with transition metals. It also forms a hydride, which is the strongest base among the hydrides of other group members that form d - d bond. The atomic number of the element is .

JEE Main 2025 (Online) 28th January Evening Shift

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