A block of mass 10 kg, moving in x direction with a constant speed of 10 m s-1, is subjected to a retarding force F = 0.1x J/m during its travel from x = 20 m to 30 m. Its final KE will be
- 275 J
- 250 J
- 475 J
- 450 J
Answer
(3) 475 J
Solution
Initial KE = 12mv2 = 12 10 102 = 500 J
Work done by the retarding force: W = - 2030 0.1x dx
= -0.05 (302 - 202) = -0.05 500 = -25 J
Work–energy theorem: Kf = Ki + W = 500 - 25 = 475 J
Answer: (3)