The magnetic force acting on a charged particle of charge -2 C in a magnetic field of 2 T acting in y direction, when the particle velocity is (2 i + 3 j) 106 m s-1, is
- 4 N in z direction
- 8 N in y direction
- 8 N in z direction
- 8 N in -z direction
Answer
(4) 8 N in -z direction
Solution
F = q( v B)
F = (-2 10-6) [(2 i + 3 j) 106 2 j ]
F = -2 [4( i j) + 6( j j) ]
i j = k and j j = 0
F = -8 k N
Force is 8 N in -z direction.
Answer: (4)