Let A, B, C be three points in xy-plane, whose position vectors are given by 3 i + j, i + 3 j and a i + (1 - a) j respectively with respect to the origin O. If the distance of the point C from the line bisecting the angle between the vectors OA and OB is 9 2, then the sum of all the possible values of a is:
- 2
- 0
- 92
- 1
Answer
(4) 1
Solution
| OA| = | OB| = 2
Bisector direction: a + b = 12 [( 3 + 1) i + (1 + 3) j ] i + j
The bisector through O is the line y = x, i.e. x - y = 0.
Distance of C(a, 1 - a) from it:
|a - (1 - a)| 2 = 9 2
|2a - 1| = 9
a = 5 or a = -4
Sum of possible values of a = 5 + (-4) = 1
Answer: (4)