A constant current was passed through a solution of AuCl4- ion between gold electrodes. After a period of 10.0 minutes, the increase in mass of cathode was 1.314 g. The total charge passed through the solution is 10-2 F. (Given atomic mass of Au = 197)
Answer
2
Solution
In AuCl4-, Au is +3 ⇒ Au3+ + 3e- Au
Moles of Au deposited = 1.314197 = 6.67 10-3 mol
∴ Charge = 3 × 6.67 10-3 F = 2 10-2 F
(The time, 10.0 min, is not needed.)
Answer: 2