PYQSide ExamsMy practice

Continuity and Differentiability · Question 15

JEE Main 2025 (Online) 7th April Evening ShiftNumericalMedium📈 Topic in 35% papers+4
1

If the function f(x) = ( x) - ( x) x - x is continuous at x = 0, then f(0) is equal to .

Answer

2

Solution

For continuity, f(0) = x 0 f(x).

Expansions near x = 0:

x = x + x33 + , x = x - x36 +

( x) = x + 3 x3 + = x + x33 + x33 + = x + 2x33 +

( x) = x - 3 x6 + = x - x36 - x36 + = x - x33 +

numerator = x3 +

Denominator: x - x = x33 + x36 + = x32 +

f(0) = x 0 x3 x32 = 2

Answer: 2

JEE Main 2025 (Online) 7th April Evening Shift

Keep practising — Continuity and Differentiability

2

Let m and n be the number of points at which the function f(x) = \x, x3, x5, , x21 \, x R, is not differentiable and not continuous, respectively. Then m + n is equal to .

JEE Main 2025 (Online) 4th April Morning Shift
3

Let f(x) = cases (1 + ax)1/x, & x < 0 \ 1 + b, & x = 0 \ (x+4)1/2 - 2(x+c)1/3 - 2, & x > 0 cases be continuous at x = 0. Then ea bc is equal to:

  1. 64
  2. 48
  3. 36
  4. 72
JEE Main 2025 (Online) 3rd April Morning Shift
4

Let f(x) = cases 3x, & x < 0 \ \1 + x + [x], x + 2[x]\, & 0 x 2 \ 5, & x > 2 cases where [.] denotes greatest integer function. If and are the number of points, where f is not continuous and is not differentiable, respectively, then + equals .

JEE Main 2025 (Online) 28th January Morning Shift

All Continuity and Differentiability PYQs →

PDFDownload Continuity and Differentiability PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Mathematics chapters