Two waves are represented by the equations y1 = a sin( t + kx + 0.57) m and y2 = a cos( t + kx) m, where x is in metre and t in second. The phase difference between them is
- 1.0 radian
- 1.25 radian
- 1.57 radian
- 0.57 radian
Answer
(1) 1.0 radian
Solution
y2 = a cos( t + kx) = a sin ( t + kx + 2 )
phase of y2 = t + kx + 1.57
Phase of y1 = t + kx + 0.57
Phase difference = 1.57 - 0.57 = 1.0 radian
Answer: (1)