Match the LIST-I with LIST-II Choose the correct answer from the options given below:
- A-III, B-I, C-II, D-IV
- A-III, B-IV, C-II, D-I
- A-III, B-IV, C-I, D-II
- A-I, B-III, C-IV, D-II
Answer
(3) A-III, B-IV, C-I, D-II
Solution
A. Williamson synthesis: R-X + R'-O-Na+ R-O-R' + NaX; the alkoxide ion (nucleophile) displaces X- by SN2 ⇒ nucleophilic substitution (III)
B. Friedel–Crafts reaction: the electrophile (R+ or RCO+, formed with anhydrous AlCl3) replaces an H of the benzene ring ⇒ electrophilic substitution (IV)
C. Bromination of vinyl benzene (styrene): Br2 adds across the side-chain C=C ⇒ C6H5CHBr-CH2Br ⇒ electrophilic addition (I)
D. Chlorination of toluene in light: chlorine free radicals replace the side-chain H ⇒ C6H5CH2Cl (then C6H5CHCl2, C6H5CCl3) ⇒ free radical substitution (II)
∴ A-III, B-IV, C-I, D-II
Answer: (3)