A monatomic gas at a pressure P, having a volume V expands isothermally to a volume 2V and then adiabatically to a volume 16V. The final pressure of the gas is (Take = 5/3)
- 64P
- 32P
- P/64
- 16P
Answer
(3) P/64
Solution
Isothermal (V → 2V): PV = P1(2V) P1 = P2
Adiabatic (2V → 16V): P1(2V) = P2(16V)
P2 = P2 ( 18 )5/3
= P2 132
= P64
Answer: (3)