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Thermodynamics (Physics) · Question 25

AIPMT 2015 (Cancelled)MCQMedium📈 Topic in 25% papers+4−1
1

Figure below shows two paths that may be taken by a gas to go from a state A to a state C. [figure] In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be

  1. 460 J
  2. 300 J
  3. 380 J
  4. 500 J

Answer

(1) 460 J

Solution

Process AB is isochoric: WAB = 0

Process BC is isobaric: WBC = P V = 6 104 2 10-3 = 120 J

Along ABC: QABC = 400 + 100 = 500 J

UAC = QABC - WABC = 500 - 120 = 380 J

Work along AC = area under the line AC:

WAC = 12(2 104 + 6 104) 2 10-3 = 80 J

Internal energy is a state function,

QAC = UAC + WAC = 380 + 80 = 460 J

Answer: (1)

AIPMT 2015 (Cancelled)

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A monatomic gas at a pressure P, having a volume V expands isothermally to a volume 2V and then adiabatically to a volume 16V. The final pressure of the gas is (Take = 5/3)

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  2. 32P
  3. P/64
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  1. P0V0
  2. 2P0V0
  3. P0V02
  4. zero
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  3. 1 + 1 -
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A system is taken from state a to state c by two paths adc and abc as shown in the figure. The internal energy at a is Ua = 10 J. Along the path adc the amount of heat absorbed dQ1 = 50 J and the work obtained dW1 = 20 J whereas along the path abc the heat absorbed dQ2 = 36 J. The amount of work along the path abc is [figure]

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  2. 12 J
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  3. TV -1 = constant
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  1. T1 - T22
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An ideal gas goes from state A to state B via three different processes as indicated in the P-V diagram. [figure] If Q1, Q2, Q3 indicate the heat absorbed by the gas along the three processes and U1, U2, U3 indicate the change in internal energy along the three processes respectively, then

  1. Q1 > Q2 > Q3 and U1 = U2 = U3
  2. Q3 > Q2 > Q1 and U1 = U2 = U3
  3. Q1 = Q2 = Q3 and U1 > U2 > U3
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  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
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