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Hydrocarbons · Question 53

AIPMT 2003MCQMedium📈 Topic in 62% papers+4−1
1

The compound CH3- CH3 |C=CH-CH3 on reaction with NaIO4 in the presence of KMnO4 gives

  1. CH3COCH3
  2. CH3COCH3 + CH3COOH
  3. CH3COCH3 + CH3CHO
  4. CH3CHO + CO2

Answer

(2) CH3COCH3 + CH3COOH

Solution

NaIO4 in the presence of a little KMnO4 (Lemieux reagent) cleaves the C=C bond oxidatively, like hot alkaline KMnO4.

KMnO4 first forms the 1,2-diol, which NaIO4 cleaves into carbonyl compounds.

Disubstituted carbon (CH3)2C= ketone: CH3COCH3 (not oxidised further).

Monosubstituted carbon =CH-CH3 CH3CHO, which is oxidised further to CH3COOH.

Products: CH3COCH3 + CH3COOH

Answer: (2)

AIPMT 2003

Keep practising — Hydrocarbons

2

The correct order of reactivity towards the electrophilic substitution of the compounds aniline (I), benzene (II) and nitrobenzene (III) is

  1. III > II > I
  2. II > III > I
  3. I < II > III
  4. I > II > III
AIPMT 2003
3

When CH3CH2CHCl2 is treated with NaNH2, the product formed is

  1. CH3-CH=CH2
  2. CH3-C CH
  3. [figure]
  4. [figure]
AIPMT 2002
4

Which alkene on ozonolysis gives CH3CH2CHO and CH3COCH3?

  1. [figure]
  2. CH3CH2CH=CHCH2CH3
  3. CH3CH2CH=CHCH3
  4. [figure]
AIPMT 2001
5

Increasing order of electrophilic substitution for following compounds [figure]

  1. IV < I < II < III
  2. III < II < I < IV
  3. I < IV < III < II
  4. II < III < I < IV
AIPMT 2000
6

In Friedel-Crafts reaction, toluene can be prepared by

  1. C6H6 + CH3Cl
  2. C6H5Cl + CH4
  3. C6H6 + CH2Cl2
  4. C6H6 + CH3COCl
AIPMT 2000

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