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Hydrocarbons · Question 52

AIPMT 2004MCQEasy📈 Topic in 62% papers+4−1
1

Reaction of HBr with propene in the presence of peroxide gives

  1. isopropyl bromide
  2. 3-bromopropane
  3. allyl bromide
  4. n-propyl bromide

Answer

(4) n-propyl bromide

Solution

As per NCERT, in the presence of peroxide HBr adds to an unsymmetrical alkene contrary to Markovnikov's rule (peroxide or Kharasch effect, free-radical mechanism):

CH3-CH=CH2 + HBr (C6H5CO)2O2 CH3-CH2-CH2Br

∵ Br adds to the terminal carbon to give the more stable 2° radical, which then takes H from HBr.

∴ Product = 1-bromopropane (n-propyl bromide).

Answer: (4)

AIPMT 2004

Keep practising — Hydrocarbons

2

The compound CH3- CH3 |C=CH-CH3 on reaction with NaIO4 in the presence of KMnO4 gives

  1. CH3COCH3
  2. CH3COCH3 + CH3COOH
  3. CH3COCH3 + CH3CHO
  4. CH3CHO + CO2
AIPMT 2003
3

The correct order of reactivity towards the electrophilic substitution of the compounds aniline (I), benzene (II) and nitrobenzene (III) is

  1. III > II > I
  2. II > III > I
  3. I < II > III
  4. I > II > III
AIPMT 2003
4

When CH3CH2CHCl2 is treated with NaNH2, the product formed is

  1. CH3-CH=CH2
  2. CH3-C CH
  3. [figure]
  4. [figure]
AIPMT 2002
5

Which alkene on ozonolysis gives CH3CH2CHO and CH3COCH3?

  1. [figure]
  2. CH3CH2CH=CHCH2CH3
  3. CH3CH2CH=CHCH3
  4. [figure]
AIPMT 2001
6

Increasing order of electrophilic substitution for following compounds [figure]

  1. IV < I < II < III
  2. III < II < I < IV
  3. I < IV < III < II
  4. II < III < I < IV
AIPMT 2000
7

In Friedel-Crafts reaction, toluene can be prepared by

  1. C6H6 + CH3Cl
  2. C6H5Cl + CH4
  3. C6H6 + CH2Cl2
  4. C6H6 + CH3COCl
AIPMT 2000

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