If the function f(x) = ( 1x )2x; x > 0 attains the maximum value at x = 1e then :
- e < e
- e2 < (2 )e
- (2e) > (2e)
- e > e
Answer
(4) e > e
Solution
f ( 1t ) = t2/t; maximum at x = 1e ⇒ f ( 1e ) > f ( 1t ) for t e
t = : e2/e > 2/
e > e (raising both sides to the power 2) ⇒ (4) is true, (1) is false
(2): t = 2 : e2/e > (2 )1/ ⇒ e2 > (2 )e ⇒ (2) is false
(3): f'(x) = -2f(x)( x + 1) > 0 on (0, 1e ) ⇒ f is increasing there
∵ 12e < 1 < 1e
f ( 12e ) < f ( 1 ) (2e)1/e < 2/
(2e) < 2e ⇒ (3) is false
Answer: (4)