The interval in which the function f(x) = xx, x > 0, is strictly increasing is
- (0, )
- (0, 1e ]
- [ 1e2, 1 )
- [ 1e, )
Answer
(4) [ 1e, )
Solution
f(x) = xx = ex x f'(x) = xx(1 + x)
xx > 0: f'(x) > 0 x > -1 x > 1e (f' = 0 only at the end point x = 1e)
f is strictly increasing on [ 1e, ) and decreasing on (0, 1e ], so (1), (2), (3) fail
Answer: (4)