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Electrostatic Potential and Capacitance

JEE Main 2024 (Online) 27th January Morning ShiftMCQEasy📈 Topic in 17% papers+4−1
Ques. 1JEE Main 2024, 27 January (Morning Shift)

An electric charge 10-6 is placed at origin (0,0) m of X − Y co-ordinate system. Two points P and Q are situated at ( 3, 3) m and ( 6,0) m respectively. The potential difference between the points P and Q will be :

  1. 3 V
  2. 6 V
  3. 0 V
  4. 3 V

Answer

(3) 0 V

Solution

V= kqr depends only on the distance from the charge.

rP= ( 3)2+( 3)2= 6 m, rQ= ( 6)2+02= 6 m

rP=rQ, P and Q lie on the same equipotential sphere

VP-VQ=0 V

Answer: (3)

Keep practising — Electrostatic Potential and Capacitance

Ques. 2JEE Main 2024, 27 January (Morning Shift)

The charge accumulated on the capacitor connected in the following circuit is (Given C = 150 ) [figure]

Ques. 3JEE Main 2024, 27 January (Evening Shift)

Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). In the light of the above statements, choose the most appropriate answer from the options given below :

  1. Both (A) and (R) are correct and (R) is the correct explanation of (A)
  2. (A) is correct but (R) is not correct
  3. Both (A) and (R) are correct but (R) is not the correct explanation of (A)
  4. (A) is not correct but (R) is correct
Ques. 4JEE Main 2024, 27 January (Evening Shift)

The electric potential at the surface of an atomic nucleus (z=50) of radius 9 10-13 cm is 106 V.

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