A 16 wire is bent to form a square loop. A 9 V battery with internal resistance 1 is connected across one of its sides. If a 4 capacitor is connected across one of its diagonals, the energy stored by the capacitor will be x2 , where x=
Answer
81
Solution
[figure]
Each side = 164=4
Side AB path ADCB: RAB= 4 124+12=3
I= 93+1= 94 A; branch ADCB: I1= 94 416= 916 A
(steady state: no current through the capacitor)
VA-VC=I1 8= 92 V
U= 12CV2= 12 4 814= 812
x=81
Answer: 81