A closed loop PQRS carrying a current is placed in a uniform magnetic field. If the magnetic forces on segments PS, SR and RQ are F1, F2 and F3 respectively and are in the plane of the paper and along the directions shown, the force on the segment QP is [figure]
- (F3 - F1)2 - F22
- F3 - F1 + F2
- F3 - F1 - F2
- (F3 - F1)2 + F22
Answer
(4) (F3 - F1)2 + F22
Solution
Net magnetic force on a closed current loop in a uniform magnetic field is zero.
FQP = -( F1 + F2 + F3)
F1 (left) and F3 (right) give a horizontal resultant (F3 - F1); F2 is vertical.
FQP = (F3 - F1)2 + F22
Answer: (4)