Consider the following reaction sequence : [figure] Compound (y) develops characteristic colour with neutral FeCl3 solution. Identify the INCORRECT statement from the following for the above sequence.
- Compound y will dissolve in NaHCO3 and evolve a gas.
- Compound x is more acidic than compound y.
- Both compounds x and y will dissolve in NaOH.
- Both compounds x and y will burn with sooty flame.
Answer
(2) Compound x is more acidic than compound y.
Solution
Compound x: C = 76.6 %, H = 6.38 %, O = 100 − 76.6 − 6.38 = 17.02 %
Moles: C = 76.612 = 6.38, H = 6.381 = 6.38, O = 17.0216 = 1.06
Ratio C : H : O = 6 : 6 : 1 empirical formula C6H6O (mass 94)
Molar mass = 2 × vapour density = 2 × 47 = 94 molecular formula C6H6O, i.e. phenol (x).
Kolbe's reaction: sodium phenoxide with CO2 (high pressure), followed by acidification, gives salicylic acid (y), which has a phenolic –OH and therefore gives a violet colour with neutral FeCl3:
[figure]
(1) Salicylic acid has a –COOH group, so it dissolves in NaHCO3 with evolution of CO2. Correct.
(2) Salicylic acid (a carboxylic acid, pKa ≈ 3) is much more acidic than phenol (pKa ≈ 10). So 'x is more acidic than y' is INCORRECT.
(3) Both phenol and salicylic acid are acidic enough to dissolve in NaOH. Correct.
(4) Both are aromatic compounds (high C : H ratio) and burn with a sooty flame. Correct.
Answer: (2)