A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is
- 4 Hz
- 3 Hz
- 2 Hz
- 1 Hz
Answer
(4) 1 Hz
Solution
v = A = 2 A
= v 2 A = 31.42 3.14 5 = 1 Hz
Answer: (4)
A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is
(4) 1 Hz
v = A = 2 A
= v 2 A = 31.42 3.14 5 = 1 Hz
Answer: (4)
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