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Hydrocarbons · Question 1

JEE Main 2026 (Online) 8th April Evening ShiftMCQMedium📈 Topic in 16% papers+4−1
1

n-Butane on monochlorination under photochemical condition gives an optically active compound "P". "P" on further chlorination gives dichloro compounds. The number of dichloro compounds obtained (ignore stereoisomers) is :

  1. 3
  2. 4
  3. 5
  4. 6

Answer

(2) 4

Solution

CH3CH2CH2CH3 Cl2, h CH3- *CHCl-CH2-CH3 (P, 2-chlorobutane, chiral)

Further chlorination replaces one H on any of the four carbons of P:

C-1: ClCH2-CHCl-CH2-CH3 (1,2-dichlorobutane)

C-2: CH3-CCl2-CH2-CH3 (2,2-dichlorobutane)

C-3: CH3-CHCl-CHCl-CH3 (2,3-dichlorobutane)

C-4: CH3-CHCl-CH2-CH2Cl (1,3-dichlorobutane)

∴ Number of dichloro compounds (ignoring stereoisomers) = 4

Answer: (2)

JEE Main 2026 (Online) 8th April Evening Shift

Keep practising — Hydrocarbons

2

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below :

  1. Both Statement I and Statement II are true
  2. Both Statement I and Statement II are false
  3. Statement I is true but Statement II is false
  4. Statement I is false but Statement II is true
JEE Main 2026 (Online) 6th April Morning Shift
3

An optically active alkyl bromide C4H9Br, reacts with ethanolic KOH to form major compound [A] which reacts with bromine to give compound [B]. Compound [B] reacts with ethanolic KOH and sodamide to give compound [C]. One molecule of water adds to compound [C] on warming with mercuric sulphate and dilute sulphuric acid at 333 K to form compound [D]. The functional group in compound D will be confirmed by :

  1. Haloform test
  2. Lucas test
  3. Silver mirror test
  4. Benedict test
JEE Main 2026 (Online) 6th April Evening Shift
4

An alkane (Y) requires 8 moles of oxygen for complete combustion and on chlorination with Cl2/h , (Y) gives only one monochlorinated product (Z). The total number of primary carbon atoms in (Y) is .

JEE Main 2026 (Online) 6th April Evening Shift
5

For the following Friedel Craft's alkylation reaction, which of the statements are correct? [figure] Choose the correct answer from the options given below :

  1. A and D only
  2. B and C only
  3. A and C only
  4. B and D only
JEE Main 2026 (Online) 5th April Morning Shift
6

An alkene (X) on ozonolysis followed by reduction gives following products. H- O \|C-H (2 moles), H- O \|C- O \|C- O \|C-H, CH3- O \|C- O \|C- O \|C-CH3 The alkene (X) is :

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
JEE Main 2026 (Online) 4th April Morning Shift
7

[figure] Compound (X) is subjected to the sequence of reactions as shown above. Molar mass of the major product (Y) formed is g mol-1. (Given molar mass in g mol-1 C : 12, H : 1, O : 16 )

  1. 90
  2. 118
  3. 160
  4. 125
JEE Main 2026 (Online) 4th April Evening Shift
8

One mole of an alkane (x) requires 8 mole oxygen for complete combustion. Sum of number of carbon and hydrogen atoms in the alkane (x) is .

JEE Main 2026 (Online) 2nd April Morning Shift
9

The compound (X) on (i) on heating in the presence of anhydrous AlCl3 and HCl gas gives 2,4-dimethyl pentane (ii) aromatization gives toluene and (iii) cyclisation gives methyl cyclohexane The correct name of compound (X) is:

  1. Hept-2-ene
  2. Hept-1,3,5-triene
  3. Heptane
  4. Hept-2,4,6-triene
JEE Main 2026 (Online) 2nd April Evening Shift
10

Given below are two statements for the following reaction sequence. [figure] In the light of the above statements, choose the correct answer from the options given below :

  1. Statement I is true but Statement II is false
  2. Both Statement I and Statement II are true
  3. Statement I is false but Statement II is true
  4. Both Statement I and Statement II are false
JEE Main 2026 (Online) 28th January Morning Shift
11

Ph-CH=CH2 [HBr](PhCOO)2 Product Consider the above reaction Identify the correct statements. Choose the correct answer from the options given below :

  1. A & E Only
  2. A, B & D Only
  3. A, C & E Only
  4. C, D & E Only
JEE Main 2026 (Online) 28th January Morning Shift

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