Electron in hydrogen atom first jumps from third excited state to second excited state and then from second excited to the first excited state. The ratio of the wavelengths 1 : 2 emitted in the two cases is
- 75
- 2720
- 275
- 207
Answer
(4) 207
Solution
Third excited state n = 4, second excited state n = 3, first excited state n = 2.
1 = R ( 1nf2 - 1ni2 )
1 1 = R ( 19 - 116 ) = 7R144
1 2 = R ( 14 - 19 ) = 5R36 = 20R144
1 2 = 207
Answer: (4)