An alpha nucleus of energy 12mv2 bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to
- 1Ze
- v2
- 1m
- 1v4
Answer
(3) 1m
Solution
At the distance of closest approach r0, the whole kinetic energy becomes electrostatic potential energy:
12mv2 = 14 0 (2e)(Ze)r0
r0 = 4Ze24 0 mv2
r0 Ze, r0 1v2 and r0 1m
Answer: (3)