An electron of a stationary hydrogen atom passes from the fifth energy level to the ground level. The velocity that the atom acquired as a result of photon emission will be
- 24hR25m
- 25hR24m
- 25m24hR
- 24m25hR
Answer
(1) 24hR25m
Solution
Here R is the Rydberg constant and m is the mass of the atom.
For the jump n = 5 n = 1:
1 = R (1 - 125 ) = 24R25
Momentum of the emitted photon:
p = h = 24hR25
By conservation of momentum, the atom recoils with equal momentum:
mv = 24hR25
v = 24hR25m
Answer: (1)