PYQSidePowered byPrepblink ExamsMy practice

Differential Equations

JEE Main 2025 (Online) 29th January Evening ShiftMCQHard📈 Topic in 71% papers+4−1
Ques. 1JEE Main 2025, 29 January (Evening Shift)

If for the solution curve y = f(x) of the differential equation dydx + ( x)y = 2 + x(1 + 2 x)2, x ( - 2, 2 ), f ( 3 ) = 310, then f ( 4 ) is equal to:

  1. 5 - 32 2
  2. 4 - 214
  3. 9 3 + 310(4 + 3)
  4. 3 + 110(4 + 3)

Answer

(2) 4 - 214

Solution

Linear D.E.: I.F. =e x dx= x

y x= (2+ x) x(1+2 x)2dx= 2 x+1( x+2)2dx (multiply by 2x)

ddx ( x x+2 )= 2 x+1( x+2)2 ⇒ y x= x x+2+C

x= 3: 310 2= 3/25/2+C ⇒ C=0

f ( 4 )= x x x+2= 1/21/ 2+2= 14+ 2= 4- 214

Answer: (2)

Keep practising — Differential Equations

Ques. 2JEE Main 2025, 28 January (Morning Shift)

Let for some function y = f(x), 0x t f(t) dt = x2 f(x), x > 0 and f(2) = 3. Then f(6) is equal to

  1. 1
  2. 6
  3. 2
  4. 3
Ques. 3JEE Main 2025, 28 January (Evening Shift)

If y = y(x) is the solution of the differential equation, 4 - x2 dydx = ( ( -1 ( x2 ) )2 - y ) -1 ( x2 ), -2 x 2, y(2) = 2 - 84, then y2(0) is equal to .

Ques. 4JEE Main 2025, 24 January (Morning Shift)

Let y=y(x) be the solution of the differential equation (xy-5x2 1+x2 )dx+ (1+x2 )dy=0, y(0)=0. Then y( 3) is equal to

  1. 5 32
  2. 152
  3. 143
  4. 2 2
Ques. 5JEE Main 2025, 24 January (Morning Shift)

Let f be a differentiable function such that 2(x+2)2f(x)-3(x+2)2=10 0x(t+2)f(t) dt, x 0. Then f(2) is equal to .

Ques. 6JEE Main 2025, 24 January (Evening Shift)

Let f:(0, ) be a function which is differentiable at all points of its domain and satisfies the condition x2f'(x)=2xf(x)+3, with f(1)=4. Then 2f(2) is equal to :

  1. 19
  2. 23
  3. 29
  4. 39
Ques. 7JEE Main 2025, 24 January (Evening Shift)

Let y=y(x) be the solution of the differential equation 2 x dydx= 2x-4y x, x (0, 2 ). If y ( 3 )=0, then y' ( 4 )+y ( 4 ) is equal to .

Ques. 8JEE Main 2025, 23 January (Morning Shift)

Let a curve y=f(x) pass through the points (0,5) and ( e 2,k). If the curve satisfies the differential equation 2(3+y)e2xdx-(7+e2x)dy=0, then k is equal to

  1. 32
  2. 8
  3. 4
  4. 16
Ques. 9JEE Main 2025, 23 January (Evening Shift)

Let x=x(y) be the solution of the differential equation y= (x-y dxdy ) ( xy ), y>0 and x(1)= 2. Then (x(2)) is equal to :

  1. 2 ( e 2 )-1
  2. 1-2 ( e 2 )2
  3. 1-2 ( e 2 )
  4. 2 ( e 2 )2-1
Ques. 10JEE Main 2025, 22 January (Morning Shift)

Let x=x(y) be the solution of the differential equation y2 dx+ (x- 1y )dy=0. If x(1)=1, then x ( 12 ) is :

  1. 32+e
  2. 12+e
  3. 3+e
  4. 3-e
Ques. 11JEE Main 2025, 22 January (Evening Shift)

If x=f(y) is the solution of the differential equation (1+y2 )+ (x-2e -1y ) dydx=0, y (- 2, 2 ) with f(0)=1, then f ( 1 3 ) is equal to :

  1. e /4
  2. e /12
  3. e /6
  4. e /3

All Differential Equations PYQs →

PDFDownload Differential Equations PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Mathematics chapters