A ray of monochromatic light is passing through an equilateral prism (ABC) as shown in the figure. The refracted ray (QR) is parallel to its base (BC) and the angle of incidence (i) is 50°. Then the angle of deviation (δ) is : [figure]
- 45°
- 55°
- 35°
- 40°
Answer
(4) 40°
Solution
∵ QR is parallel to the base BC of the equilateral prism ⇒ the ray passes symmetrically (minimum deviation).
⇒ r1 = r2 = A2 = 30° and e = i = 50°
= i + e - A = 50° + 50° - 60°
∴ = 40°
Answer: (4)