The lens combination as shown in the figure, consists of two lenses, L1 and L2, of the focal lengths +10 cm and -10 cm, respectively. The position of the image formed is: [figure]
- 60 cm to the right of the concave lens
- 20 cm to the left of the concave lens
- 60 cm to the left of the concave lens
- 30 cm to the right of the concave lens
Answer
(3) 60 cm to the left of the concave lens
Solution
For lens L1 (f1 = +10 cm, u1 = -30 cm):
1v1 - 1u1 = 1f1 1v1 - 1-30 = 110 v1 = +15 cm.
This image acts as a virtual object for L2. Separation between lenses is d = 3 cm.
u2 = +(15 - 3) = +12 cm.
For lens L2 (f2 = -10 cm):
1v2 - 1u2 = 1f2 1v2 - 112 = - 110 1v2 = - 110 + 112 = - 160 v2 = -60 cm.
Thus, the final image is formed 60 cm to the left of the concave lens.
Answer: (3)