Monochromatic light of wavelength 500 nm is used in Young's double slit experiment. An interference pattern is obtained on a screen. When one of the slits is covered with a very thin glass plate (refractive index = 1.5), the central maximum is shifted to a position previously occupied by the 4th bright fringe. The thickness of the glass-plate is .
Answer
4
Solution
The plate adds an extra optical path ( - 1)t, and a shift of n fringes needs a path difference n :
( - 1)t = n
(1.5 - 1)t = 4 500 10-9
t = 2 10-60.5 = 4 10-6 m = 4
Answer: 4