The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is
- 23.6 MeV
- 2.2 MeV
- 28.0 MeV
- 30.2 MeV
Answer
(1) 23.6 MeV
Solution
12H + 12H 24He
Binding energy of two deuterons = 2 (2 1.1) = 4.4 MeV
Binding energy of helium = 4 7.0 = 28.0 MeV
Energy released = 28.0 - 4.4 = 23.6 MeV
Answer: (1)