A nucleus mnX emits one particle and two particles. The resulting nucleus is
- m-6n-4Z
- m-6nZ
- m-4nX
- m-4n-2Y
Answer
(3) m-4nX
Solution
Emission of one particle (42He): mass number decreases by 4, atomic number decreases by 2:
mnX m-4n-2Y + 42He
Emission of two particles ( 0-1e): mass number unchanged, atomic number increases by 2:
m-4n-2Y m-4nX + 2 0-1e
The atomic number is again n, the product is an isotope of the same element X.
Answer: (3)