Applying the principle of homogeneity of dimensions, determine which one is correct, where T is time period, G is gravitational constant, M is mass, r is radius of orbit.
- T2 = 4 2 rGM2
- T2 = 4 2 r3
- T2 = 4 2 r3GM
- T2 = 4 2 r2GM
Answer
(3) T2 = 4 2 r3GM
Solution
[G] = M-1L3T-2 and [T2] = T2 (4 2 is dimensionless)
(A): [ rGM2 ] = L M-1L3T-2 M2 = M-1L-2T2 ⇒ (A) is wrong
(B): [r3] = L3 ⇒ (B) is wrong
(C): [ r3GM ] = L3 M-1L3T-2 M = T2 ⇒ (C) is correct
(D): [ r2GM ] = L-1T2 ⇒ (D) is wrong
only in (C) both sides have the same dimensions (T2)
Answer: (3)