10 divisions on the main scale of a Vernier calliper coincide with 11 divisions on the Vernier scale. If each division on the main scale is of 5 units, the least count of the instrument is :
- 511
- 1011
- 5011
- 12
Answer
(1) 511
Solution
11 VSD=10 MSD 1 VSD= 1011 MSD
LC = 1 MSD - 1 VSD
LC= (1- 1011 )MSD= 111 5
LC= 511 units
Answer: (1)