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Sequences and Series · Question 27

JEE Main 2026 (Online) 22nd January Morning ShiftMCQEasy📈 Topic in 55% papers+4−1
1

If the sum of the first four terms of an A.P. is 6 and the sum of its first six terms is 4, then the sum of its first twelve terms is

  1. -26
  2. -20
  3. -24
  4. -22

Answer

(4) -22

Solution

Let the first term be a and the common difference d. Sn = n2[2a + (n-1)d]

S4 = 2(2a + 3d) = 6

2a + 3d = 3 ...(i)

S6 = 3(2a + 5d) = 4

2a + 5d = 43 ...(ii)

(ii) - (i): 2d = 43 - 3 = - 53

d = - 56

From (i): 2a = 3 + 52 = 112

S12 = 6(2a + 11d)

= 6 ( 112 - 556 )

= 33 - 55 = -22

Answer: (4)

JEE Main 2026 (Online) 22nd January Morning Shift

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2

Suppose a, b, c are in A.P. and a2, 2b2, c2 are in G.P. If a < b < c and a + b + c = 1, then 9(a2 + b2 + c2) is equal to .

JEE Main 2026 (Online) 22nd January Evening Shift
3

Let a1, a2, a3, be a G.P. of increasing positive terms such that a2 a3 a4 = 64 and a1 + a3 + a5 = 8137. Then a3 + a5 + a7 is equal to :

  1. 3256
  2. 3252
  3. 3248
  4. 3244
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4

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5

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  1. 3
  2. 6
  3. 9
  4. 12
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6

Let a1, a22, a322, , a1029 be a G.P. of common ratio 1 2. If a1 + a2 + + a10 = 62, then a1 is equal to:

  1. 2 - 1
  2. 2( 2 - 1)
  3. 2 - 2
  4. 2(2 - 2)
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7

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  1. 23
  2. 14
  3. 18
  4. 15
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8

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  1. 18
  2. 216
  3. 36
  4. 72
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9

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  1. 65
  2. 56
  3. 70
  4. 64
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10

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  1. 757
  2. 755
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11

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  1. 40870
  2. 41880
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