Let O be the origin and the position vectors of A and B be 2 i+2 j+ k and 2 i+4 j+4 k respectively. If the internal bisector of meets the line AB at C, then the length of OC is
- 32 34
- 23 31
- 23 34
- 32 31
Answer
(3) 23 34
Solution
OA= 4+4+1=3, OB= 4+16+16=6
[figure]
Angle-bisector theorem: AC:CB=OA:OB=1:2
OC= 2 OA+ OB3= 6 i+8 j+6 k3
OC= 36+64+363= 1363= 23 34
Answer: (3)