The position vectors of the vertices A, B and C of a triangle are 2 i-3 j+3 k, 2 i+2 j+3 k and - i+ j+3 k respectively. Let l denote the length of the angle bisector AD of where D is on the line segment BC, then 2l2 equals :
- 45
- 50
- 42
- 49
Answer
(1) 45
Solution
AB=5 j =5; AC=-3 i+4 j =5
[figure]
BD:DC=AB:AC=1:1 (angle bisector theorem) D is the mid-point of BC
D= ( 12, 32,3 )
l2=AD2= (2- 12 )2+ (-3- 32 )2+02= 94+ 814= 452
2l2=45
Answer: (1)