A point charge Q is placed inside a cavity within a solid isolated conducting sphere. Consider points A, B and C as shown in the figure, where the magnitudes of the electric fields are EA, EB, EC, respectively. The points B and C are at the same distance from the center of the solid sphere. The correct option is : [figure]
- EA 0, EB < EC
- EA = 0, EB = EC
- EA 0, EB = EC
- EA = 0, EB > EC
Answer
(3) EA 0, EB = EC
Solution
1. Point A is inside the cavity containing point charge Q, so the electric field at A is non-zero (EA 0).
2. By electrostatic shielding, the cavity charges induce a total charge +Q on the outer surface of the isolated spherical conductor. Because the conductor has a spherical outer boundary, this outer surface charge distributes completely symmetrically and uniformly.
3. The electric field outside the sphere behaves as if the entire charge +Q were concentrated at the centre of the sphere. Since points B and C are at equal distances from the centre of the sphere, their field magnitudes are equal: EB = EC.
Thus, EA 0 and EB = EC.
Answer: (3)