MnO42-, in acidic medium, disproportionates to :
- MnO4- and MnO
- MnO4- and MnO2
- Mn2O7 and MnO2
- Mn2O7 and MnO
Answer
(2) MnO4- and MnO2
Solution
In MnO42- (manganate), Mn is in the +6 state. In acidic (or neutral) solution it disproportionates:
3MnO42- + 4H+ 2MnO4- + MnO2 + 2H2O
Mn: +6 → +7 (in MnO4-, oxidation) and +6 → +4 (in MnO2, reduction).
Answer: (2)