If z = 32 + i2, i = -1, then (z201 - i )8 is equal to
- 1
- 0
- -1
- 256
Answer
(4) 256
Solution
z = 6 + i 6 = ei /6
z201 = ei 201 /6 = ei(32 + 3 /2)
= 3 2 + i 3 2 = -i
z201 - i = -2i
(z201 - i)8 = (-2i)8 = 28 i8 = 256
Answer: (4)
If z = 32 + i2, i = -1, then (z201 - i )8 is equal to
(4) 256
z = 6 + i 6 = ei /6
z201 = ei 201 /6 = ei(32 + 3 /2)
= 3 2 + i 3 2 = -i
z201 - i = -2i
(z201 - i)8 = (-2i)8 = 28 i8 = 256
Answer: (4)
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